Old friends gathered in eureka.
This is a logic game for all ages.
And we, in turn, decided to help you with the passage of this game.
In the game you will find achievements / awards that will help you compete and lead among all players!
Walkthrough:
- Level 51
Question: The janitor Petya was walking past house number 5 with his sister. He said that he would come to visit his nephew. The sister said, "Well, since I don't have a nephew, I'll go to my house." Who is the sister of the mysterious nephew?
Answer: MOTHER
Solution: The sister was the mother of the boy
- Level 52
Question: Friends drank tea with milk. After drinking half a cup of tea, Masha poured milk into the cup to the top. Then Masha drank a third of the resulting tea with milk and added the same amount of milk. Then she drank a sixth of the resulting milk tea, filled the cup with milk to the top and drank it all to the end. What did Masha drink more in the end: milk or tea?
Answer: SAME
Solution: Masha drank exactly one glass of tea, because initially there was 1 cup of tea and it was not topped up. Accordingly, milk was then added to half a glass, and this is 1/2 of its part, then milk was added again, this time already 1/3 glass, and the last time milk was added already 1/6 cup. It turns out that the sum of these parts gives 1/2 + 1/3 + 1/6 = 1 glass.
- Level 53
Question: If one cubic meter is divided into its constituent cubic millimeters and joined together by faces in one straight line, then how long will this line be? Give your answer in meters.
Answer:1000000
Solution: There are 1000 x 1000 x 1000 cubic millimeters in one cubic meter.
In a cube, in 1 cubic millimeter, the face is also one millimeter long. It turns out that the line will be equal to the length of 1,000 * 1,000 * 1,000 * 1 = 1,000,000,000 millimeters. So in meters it is 1,000,000. And in kilometers it will be 1000.
- Level 54
Question: They gave it to you, and it belongs to you now. You never gave it to anyone, but all your friends use it. What is this?
Answer: NAME
- Level 55
Question: Four married couples celebrated a birthday. While drinking tea, Lena ate 3 sweets, Katya ate 2 sweets, Alina 4, and Anya ate one candy. Anton ate as much as his wife, Ilya - twice as much as his wife, Alexander - three times as much as his wife, and Alexei - 4 times as much as his wife. If everyone present ate 32 sweets together, could you tell me the name of Alexander's wife?
Answer: ANIA
Solution: Alexander is married to Anya, ate 3 sweets. Anton is married to Lena, he ate 3 sweets. Ilya - on Alina, ate 8 sweets. Alexey - on Katya, ate 8 sweets.
- Level 56
Question: There are 101 coins in a bag. Among them there is one fake, which differs from the others in weight. Finding a counterfeit coin is not required. How many weighings can be used to determine whether a counterfeit coin is lighter or heavier?
Answer: 2
Solution: First you need to weigh 50 and 50 coins. If they are equal in weight, then you need to take the remaining one coin and put it in the left pile (or in the right pile, it doesn’t matter which pile, because both initially have 50 coins) instead of one of the ones there. Next, we look if the left pile is heavier, therefore, the counterfeit coin is heavier. If the pile on the left is lighter, then the counterfeit coin is lighter.
If the piles of 50 and 50 coins are not equal, then we take a heavier pile and divide it into two piles of 25 coins. If the weight of the piles is the same, then the counterfeit coin is lighter. If the weights of the piles are not the same, then the counterfeit coin is heavier than the real coins.
- Level 57
Question: A group of schoolchildren went on a bike ride. First-graders rode tricycles, and seniors rode two-wheeled bicycles. How many high school students went on a hike if the total number of wheels is known to be 12?
Answer: 3
Solution: The problem indicates the plural number of participants in the bike trip (first graders and high school students), which means there are 2 or more of them. Suppose there are only 2 first-graders on a tricycle, so the total number of their wheels is 6, there are 6 more wheels left.
Since high school students are also either 2 or more. This means that the minimum number of their wheels is 4. Accordingly, 6 + 4 = 10, there are 2 more wheels left, which means that another high school student rode with them on a two-wheeled bicycle.
So, three high school students rode a two-wheeled bicycle and 2 first graders rode a tricycle.
- Level 58
Question: A group of pensioners were playing loto in the yard. In the midst of excitement, one chip flew off and broke the headlight of the Cossack janitor Petrovich. Zakharych said: "This is either Nikitich or Lvovich." Nikitich said: "It was not me and not Platonich who did it." Ivanych said: "In my opinion, one of them is telling the truth, and the other is not." And Platonych said: Ivanych, you are mistaken. And the janitor's wife at that moment was sitting on a bench and saw everything. She said that only one pensioner lied, but from whose hand the fatal chip flew out, she did not tell. But after all you and guess.
Answer: LVOVICH
Decision: Only Ivanych deceived about the broken headlight. Since Zakharych told the truth that it was either Nikitich or Lvovich. But Nikitich told the truth to himself that he did not break the headlight, and Platonych did not break it.
- Level 59
Question: Old friends gathered in a bar and began to discuss the gifts that each of them presented to his wife on March 8th. One said that his gift can accelerate to 100 km / h in 6 seconds, this is a Porsche. The second said that he gave his wife a Ferrari - up to 100 in 4 seconds. And the third said that his gift reaches 100 in 2 seconds, which does not please his wife at all. What did the third man give?
Answer: SCALES
- Level 60
Question: At some point, he stopped near one object and said: "This is red." Mom objected: "No, she's black." "Why is she white?" Vova asked. "Because it's green." What did Vova discuss with his mother?
Answer: CURRANT
Eureka game! logical tasks - answers and tips for the application for phone and tablet (android), iphone and ipad (ios). Solutions and explanations for all levels of the game.
Question: The janitor Petya was walking with his sister past house number 5. He said that he would come to visit his nephew. The sister said, "Well, since I don't have a nephew, I'll go to my house." Who is the sister of the mysterious nephew?Answer: MOTHER.
Solution: The sister was the boy's mother. Question: Friends drank tea with milk. After drinking half a cup of tea, Masha poured milk into the cup to the top. Then Masha drank a third of the resulting tea with milk and added the same amount of milk. Then she drank a sixth of the resulting milk tea, filled the cup with milk to the top and drank it all to the end. What did Masha drink more in the end: milk or tea?
Answer: EQUALLY.
Solution: Masha drank exactly one glass of tea, because initially there was 1 cup of tea and it was not topped up. Accordingly, milk was then added to half a glass, and this is 1/2 of its part, then milk was added again, this time already 1/3 glass, and the last time milk was added already 1/6 cup. It turns out that the sum of these parts gives 1/2 + 1/3 + 1/6 = 1 glass. Question: If one cubic meter is divided into its constituent cubic millimeters and joined together by faces in one straight line, then how long will this line be? Give your answer in meters.
Answer: 1000000.
Solution: There are 1000 x 1000 x 1000 cubic millimeters in one cubic meter.
In a cube, in 1 cubic millimeter, the face is also one millimeter long. It turns out that the line will be equal to the length of 1,000 * 1,000 * 1,000 * 1 = 1,000,000,000 millimeters. So in meters it is 1,000,000. And in kilometers it will be 1000. Question: They gave it to you, and it belongs to you now. You never gave it to anyone, but all your friends use it. What is this?
Answer: NAME. Question: Four married couples celebrated a birthday. While drinking tea, Lena ate 3 sweets, Katya ate 2 sweets, Alina 4, and Anya ate one candy. Anton ate as much as his wife, Ilya - twice as much as his wife, Alexander - three times as much as his wife, and Alexei - 4 times as much as his wife. If everyone present ate 32 sweets together, could you tell me the name of Alexander's wife?
Answer: ANYA.
Solution: Alexander is married to Anya, ate 3 sweets. Anton is married to Lena, he ate 3 sweets. Ilya - on Alina, ate 8 sweets. Alexey - on Katya, ate 8 sweets. Question: There are 101 coins in the bag. Among them there is one fake, which differs from the others in weight. Finding a counterfeit coin is not required. How many weighings can be used to determine whether a counterfeit coin is lighter or heavier?
Answer: 2.
Solution: First you need to weigh 50 and 50 coins. If they are equal in weight, then you need to take the remaining one coin and put it in the left pile (or in the right pile, it doesn’t matter which pile, because both initially have 50 coins) instead of one of the ones there. Next, we look if the left pile is heavier, therefore, the counterfeit coin is heavier. If the pile on the left is lighter, then the counterfeit coin is lighter.
If the piles of 50 and 50 coins are not equal, then we take a heavier pile and divide it into two piles of 25 coins. If the weight of the piles is the same, then the counterfeit coin is lighter. If the weights of the piles are not the same, then the counterfeit coin is heavier than the real coins. Question: A group of students went on a bike ride. First-graders rode tricycles, and seniors rode two-wheeled bicycles. How many high school students went on a hike if the total number of wheels is known to be 12?
Answer: 3.
Solution: The problem indicates the plural number of participants in the bike trip (first graders and high school students), which means there are 2 or more of them. Suppose there are only 2 first-graders on a tricycle, so the total number of their wheels is 6, there are 6 more wheels left.
Since high school students are also either 2 or more. This means that the minimum number of their wheels is 4. Accordingly, 6 + 4 = 10, there are 2 more wheels left, which means that another high school student rode with them on a two-wheeled bicycle.
So, three high school students rode a two-wheeled bicycle and 2 first graders rode a tricycle. Question: A group of pensioners were playing loto in the yard. In the midst of excitement, one chip flew off and broke the headlight of the Cossack janitor Petrovich. Zakharych said: "This is either Nikitich or Lvovich." Nikitich said: "It was not me and not Platonich who did it." Ivanych said: "In my opinion, one of them is telling the truth, and the other is not." And Platonych said: Ivanych, you are mistaken. And the janitor's wife at that moment was sitting on a bench and saw everything. She said that only one pensioner lied, but from whose hand the fatal chip flew out, she did not tell. But after all you and guess.
Answer: LVOVICH.
Solution: Only Ivanovich deceived about the broken headlight. Since Zakharych told the truth that it was either Nikitich or Lvovich. But Nikitich told the truth to himself that he did not break the headlight, and Platonych did not break it. Question: Old friends gathered at the bar and began to discuss the gifts that each of them presented to his wife on March 8th. One said that his gift can accelerate to 100 km / h in 6 seconds, this is a Porsche. The second said that he gave his wife a Ferrari - up to 100 in 4 seconds. And the third said that his gift reaches 100 in 2 seconds, which does not please his wife at all. What did the third man give?
Answer: SCALES. Question: At some point, he stopped near one object and said: "This is red." Mom objected: "No, she's black." "Why is she white?" - asked Vova. "Because it's green." What did Vova discuss with his mother?
Answer: CURRANT. Question: Vasya wrote down on the board all the five-digit numbers, in which each digit is either equal to both neighboring ones, or differs from the neighboring ones by exactly one - from one to the smaller, and from the other to the larger side. How many numbers written by Vasya have the number "5" in their entry?
Answer: 11.
Solution: 12345 23456 34567 45678 56789 are five numbers
inverse: 98765 87654 76543 65432 54321 - these are five more numbers
and plus one 55555 - a total of eleven. Question: Two mathematicians of genius who had not reached retirement age met after a long break to take a walk down the alley. Petya at that time was sitting in the bushes and overheard their strange conversation:
- Well, do you have children?
- Three sons.
- How old are they?
- If you multiply, it will be just your age.
- (A little thought). This information is not enough for me.
“If you add up their ages, you get today's number.
- (Again after reflection). No. until I can figure it out.
- Well, the middle son loves to dance.
- Ah, it's clear now!
Petya fell into a stupor in the bushes. Can you determine the age of each of the sons (write the ages in numbers separated by a space without commas)?
Answer: 1 5 8.
Solution: A mathematician knows the product and sum of three integers and cannot determine them. This means that these numbers are such that they cannot be uniquely determined, so the sum and product of two triples of numbers are equal. Further, by sorting through all the possible numbers that can be according to the condition of the problem, for example, you can sort out from 20 to 60 years, then you can understand that in almost all these cases these numbers are decomposed into a product of three factors that have different sums. It turns out that there are only 2 exceptions:
36 \u003d 1 * 6 * 6 \u003d 2 * 2 * 9, then the sum of the factors is 13,
40 \u003d 2 * 2 * 10 \u003d 1 * 5 * 8, here the sum of the factors is 14.
Accordingly, only the last option is suitable, since the last clue excludes children of the same age. Question: The little dwarf designed a book of children's fairy tales. He had already finished with the drawings and started putting down the page numbers. To do this, he needed 534 digits. He put a number on every page, starting with the first. How many pages are in the textbook?
Answer: 214.
Solution: For numbering from page 10 to page 99, 2 digits have already been used, it turns out that 180 digits ((99 - 10) * 2 digits in each number + 2 digits in number 10). For numbering from page 100 to page 200, 303 digits will be used ((200 - 100) * 3 digits in each number + 3 digits in 100).
A total of 492 digits were used (9 + 180 + 303).
The little dwarf needed 534 digits - 492 digits received from the digit in the end = 42 digits remain. We divide 42 digits by 3 (since the next number will be three-digit, namely 201) and we get 14, respectively, 200 + 14 = 214 pages were numbered by the gnome. Question: Winnie the Pooh and Piglet found two identical bricks. They laid them on a smooth board, one flat and the other on edge. They really wanted to know which brick would slide first if they tilted the board.
Answer: BOTH or SAME.
Solution: The bricks will start sliding at the same time, both at the same time. After all, both bricks immediately press on a smooth board with the same force. And this means that the friction forces that they have to overcome when sliding on a smooth board are also the same. The specific friction forces per square centimeter of the area of contact between the bricks and the board, of course, are not equal. But the total friction forces acting on the bricks, which are equal to the product of the specific friction force and the contact surface area, are the same. Question: Belka and Strelka flew by helicopter from Baikonur. After taking off, the helicopter flew due north for 500 km, then turned east and flew another 500 km, then turned south and flew another 500 km, and finally, turning west, flew the last 500 km. Where did he land (fill in the answer option number)?
1) in the same place where you left
2) north
3) south
4) to the west
5) east
Answer: 5.
Solution: East of the departure point. The meridians of the Earth are approaching to the north, and the helicopter was flying not in a square, but in a trapezoid. Question: Four friends decided to give the girls flowers. On the morning of the next day, no one could remember exactly what happened yesterday before the general booze and who gave what flowers to whom. Together we managed to remember that:
1. Each of the four girls was given one bouquet;
2. All the girls had different flowers;
3. Yuri has not seen Katya and Marina all day;
4. Dima could not buy a bouquet of roses;
5. Andrei did not give flowers to either Olya or Marina;
6. George at first wanted to give a bouquet to Lena or Katya, but then changed his mind;
7. Neither Lena nor Olya met Dima;
8. Katya never received her favorite mimosas;
9. Andrei did not buy flowers with the letter "G";
10. Neither Lena nor Olya were given roses;
11. Yuri did not have time to buy gladioli;
12. George remembered seeing bouquets of carnations and mimosas from his friends;
13. As a result, Marina did not have the carnations and gladioli that she expected to receive;
14. Lena boasted to her friend that she "didn't get these cheap mimosas."
Who and what gave Katya?
Answer: ANDREY ROZY.
Solution: Yuri gave carnations to Lena. Andrei gave roses to Katya. Dima gave mimosa to Marina. Georgy gave gladioli to Olya. Question: In A.P. Chekhov's story "The Tutor", the schoolboy Egor Ziberov failed to solve the arithmetic problem, and the father of the student being rehearsed, the retired provincial secretary Udodov, clicked on the abacus and received the correct answer. Can you solve this problem arithmetically? Here she is.
The merchant bought 138 arshins of black and blue cloth for 540 rubles. The question is, how many arshins did he buy and that other one, if the blue one cost 5 rubles per arshin, and the black one - 3 rubles?
Answer: 75 63.
Solution: If the merchant purchased one type of cloth, for example, blue, then he would pay 138 * 5 rubles for it, it turns out 690 rubles. The resulting difference of 150 rubles was obtained due to the fact that black cloth increased in price by exactly 2 rubles. It turns out that there were 150/2 = 75 arshins of black cloth, and 138 - 75 = 63 arshins of blue cloth.
Question: Solve the problem: Problem 59: Old friends gathered in a bar and began to discuss the gifts that each of them presented to his wife on March 8th. One said that his gift can accelerate to 100 km / h in 6 seconds, this is a Porsche, the second said that he gave his wife a Ferrari - up to 100 in 4 seconds. And the third said that his gift reaches 100 in 2 seconds, which does not please his wife at all. What did the third man give?
Solve the problem: Problem 59: Old friends gathered in a bar and began to discuss the gifts that each of them gave his wife on March 8th. One said that his gift can accelerate to 100 km / h in 6 seconds, this is a Porsche, the second said that he gave his wife a Ferrari - up to 100 in 4 seconds. And the third said that his gift reaches 100 in 2 seconds, which does not please his wife at all. What did the third man give?
Answers:
hahahaha, I'm too dumb to write this)
Scales 100 kg in 2 seconds Weight of his wife
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hTPOYM ABOUT IPSKLH YLPOH. NPS NYULB CHETOHMBUSH ABOUT NEUFP. LBCEFUS, NSCH OBYUYOBEN OBIPDYFSH PVEIK SHCHL.
23 PLFSVTS.
ULBBM LPPH, UFP LPZFY MHYUYE CHUEZP FPYUBFUS P NSZLHA NEVEMSH. FERETSCH UYDYF H BRETFPK LMBDPCHLE Y PTEF NBFETOSHCHE YUBUFHYLY P DPNPCHSHCHI. LUFBFY, OELPFPTSCHE PYUEOSH DBCE OYUEZP.
24 PLFSVTS.
iBIBMA WOSMY ZYRU. rTYIPDYM WEZPDOS. YYHYUBA BOBFPNYA. rYYHF, UFP PYUEOSH MEZLP MPNBEFUS LMAYUYGB. OB OEK Y PUFFBOCHINUS.
25 PLFSVTS.
IPSKLB IPUEF UBCHEUFY UPVBLH. LPF UUSCHF PE CHUEI UNSCHUMBI Y KHZMBI. rPUNPFTYN, LFP LPZP...
29 PLFSVTS.
bChFTB DPMTSOSCH RTYCHEEFY UPVBLH. LPF RPUFPSOOP HNSCHCHBEFUS Y DEMBEF CHYD, YUFP ENH RP ZhYZH. b UBN CHUETB HVYTBMUS CH LMBDPCHLE Y HUYMUS BLTSCHCHBFSH b UPVPK DCHETSH.
30 PLFSVTS.
pK ... fPMSHLP RTPTTSBMUS! RTYCHEMY HER. OE BOBA LBLPK RPTPDSCH, OP YЪ LFYI ... LPFPTSCHN, YUFPVSCH YBZ UDEMBFSh, OKHTSOP YOUKHMSHF RETETSYFSH. lBTNBOOSCHK REU! LUFBFY, LPF UIDYF CH LMBDPCHLE Y LTYUYF PFFHDB: "Oh UFP FBN?". ULBBM ENH, UFP RTYCHEMY CHPMLPDBCHB. FPF PFCHEFIM NOE, UFP RPLB EEE ЪBOSF, NOPZP TBVPFSCH Y OPYUECHBFSH VKhDEF CH LMBDPCHLE. b ZPMPUPL FP DDTCYF ...
31 PLFSVTS.
OBLPNYMUS IN iBMLPN. sFP FBL ЪPCHHF FFPZP OENPEOPZP. rPLB ЪDPTPCHBMUS U OIN, FPF RBTH TBb PVDEMBMUS RPD UEVS. IPSKLB OBSCCHCHBEF EZP RHUILPN YOE MKHRIF. LBL FP DBCE BL LPFB PVIDOP...
1 OPSVTS.
IMMPHYO. OE PFNEYUBA RTYOGYRYBMSHOP. oE GENERAL FFP CHUE. b ChPF IPSKLB PVCHEYBMBUSH YuEUOPPLN Y IPDIF U LTEUFPN RP LCHBTFYTE. nPTSEF VSHCHFSH, S RTPUFP ZTPNLP YZTBM ABOUT VBMBMBKLE?
2 OPSVTS.
OPYUSHA CHCHYOM LPF. OH LBL CHCHYEM. . chshchrpm. RETEDCHYZBEFUS RP LCHBTFYTE LTBKOE NEDMEOOP. noe ZPCHPTYF, UFP RTPUFP ENH OELKhDB UREYYFSH, UFP PO HUFBM RPUME HVPTLY. rPOSFOP. pULHEF.
3 OPSVTS.
and CHUE FBLY SING CHUFTEFYMYUSH. fBLHA ULPTPUFSH VEZB WITH CHYDE FPMSHLP FPZDB, LPZDB IBIBMSh VETSBM ABOUT FPMYUPL, RPUME RPDUSCHRBOOPZP OBNY UMBVYFEMSHOPZP. OE BOBA DBCE, LFP YOYI VPMSHIE YURKHZBMUS.
4 OPSVTS.
rPULPMShЪOHMUS CH RTYIPTSEK. FERETSH KOBA, LFP VPMSHIE YURKHZBMUS. UFTBI PYUEOSH ULPMSHLYK Y, PRTEDEMEOOP, RBIOEF UPVBYUSHNY DETSHNPN.
5 OPSVTS.
rPUBDYM YI ЪB UFPM RETEZPCHPTCH. YuETE RSFSH NYOHF RPUME OBYUBMB BUEDBOIS, IPSKLB YCHSCHTBOHMB UP UFPMB LBTsDPZP RP PYUETEDY. pFLHDB NOE OBFSH, UFP UFP UFPM RETEZPCHPTCH - FFP NEFBZHPTTB? RETEOEUMY BUEDBOYE ABOUT IEUFPE. h LMBDPCHLE.
6 OPSVTS.
LPF PFNEYUBM DEOSH TBCHEDUILB. nSPMYUB. h bubde.
7 OPSVTS.
CHUE UPUFPSMPUSH. iBML ULBBM, UFP OILBLYI FETTYFPTYBMSHOSHCHI RTEFEOYK X OEZP OEF, BCHUE, UFP PO IPUEF - LFP DPTSYFSH DP UNETFY. LPF BYUYFBM URYUPL UCHPYI FTEVPCHBOIK. bNEFYM, YuFP EUMY UMHYBFSH EZP, BLTSCHCH ZMBB, NPTsOP RTEDUFBCHYFSH, UFP UMHYBEYSH TSYTYOPCHULPZP.
8 OPSVTS.
LPF IPDIF RP DPNH LBL DENVEMSH. UPVBLECHYU PVTBEBEFUUS L OENH OE YOBYUE, LBL "fPCHBTYE uFBTPUMHTSBEK". FPF ЪB LFP PFDBEF ENH NBUMP.
9 OPSVTS.
ULBBM UPVBLECHYUKH, UFP LPF VPIFUS NHIPVPCLH. pFCHEFYM NOE, YUFP TSYOSH - LFP MYYSH YUETEDB UMHYUBKOSHCHI UPVSCHFIK, UZEOETYTPCHBOOSCHI PTEDEMEOOOSCHN PVTBPN, OEYNEOOP RTYCHPDSEYI L PRTEDEMEOOPNKh PLPOYUBOYA. ULBBM LPPH, UFPVSCH RETERTSFBM ChBMETSHSOLV.
10 OPSVTS.
iBML HLHUYM IBIBMS b OPZH. FPF YNSLOKHM EZP RP NPTDE, RPFPNH YuFP RPDHNBM, UFP EZP HLKHUYMB NHIB. GET OUT H LMBDPCHLE, ZPFCHMY RMBO NEUFI. OBYEM ABOUT RPMLE TSKHTOBM "CH NYTE TSYCHPFOSHCHI". LPF UDEMBM CHYD, UFP LFP OE EZP, OP RPRTPUYME OE CHCHLIDSCCHBFSH.
13 OPSVTS.
oENPEOSCHK RETEZTSCH IBIBMA YOKHTLY. LBL CHYDOP RP DBFE, FFP ЪBOSM NOPZP READ. pFICHBFIM, EUFEUFCHEOOP, LPF. UPVBLECHYU CHUA OPYUSH PFTSYNBMUS.
14 OPSVTS.
OBYMY X and BMLB LOYZH OYGIE. CHEUSH CHEETS TBUUKHTSDBMY Y DYULHFYTPCHBMY U LPFPN. rTYYMY L CHSHCHCHPDH, UFP DCHETSH MKHYUYE RPDRYTBFSH FPMLPCCHN UMPCHBTEN, YVP PO FTSEMEE.
15 OPSVTS.
uOPCHB RTYIPDYM UBOFEIOIL. ULBBM, UFP RPUME RTPYMPZP TBB PO VTPUYM RJFSH. with EZP RPDTBCHYM Y RPTsBM THLH. FERETSCH PO EEE Y EUFSH VTPUYF.
17 OPSVTS.
iBML TBUULBSCCHBM OBN, LBL NOPZP YOFETEUOPZP ЪB CHIPDOK DCHETSHA. NSC U LPFPN FBN OH TBH OE VSHMY. LPF OE CHETYF, UFP LTPNE OEZP UHEEUFCHHAF DTHZYE LPFSHCH.
18 OPSVTS.
iPSKLB HETZBEF CH PFRHUL. oENPEOPZP VETEF U UPVPK, B LPF PUFBEFUUS DPNB. rTPUYMB UPUEDB RTYUNBFTYCHBFSH OB OIN. b NEOS OEMSHЪS RPRTPUYFSH? b. . oh db...
19 OPSVTS.
UFSHTIME X IPSKLY CHFPTSCHE LMAYUY PF LCHBTFYTSCH. bChFTB CHSHCHIPDYN CH RPIPD. b UEKYUBU - PFVPK.
20 OPSVTS.
CHCHIPDYN. DOECHOIL, OB CHUSLYK UMHYUBK, CHSM U UPVPK. OH TBH OE CHYDEM X LPFB FBLYI VPMSHYI BTBYULCH. ZPCHPTYF, UFPVSCH MKHYUYE CHYDEFSH. b RP-NPENH, RTPUFP PYULHEF. rPLB URHULBMYUSH RP MEUFOIGE, LPF FTY TBB URTPUYM, CHCHLMAYUYMY MY NSCH HFAZ. rTYYMPUSH CHETOHFSHUS. LPF ULBBM, UFP HCE RPDOP Y MEZ DTSCHIOHFSH.
21 OPSVTS.
RETCHSHCHK TB HCHYDEMY DPNPZHPO. PI Y BDULPE KHUFTPKUFCHP. tsDBMY RPLB LFP-OYVHDSH CHSHKDEF. CHCHIPDYM UPUED. hЪSM LPFB Y PFOEU DPNPC. rTYYMPUSH CHPCHTBEBFSHUS. LPF LTYUBM, UFP ON UBNPUFPSFEMSHOSHCHK Y CHRTBCHE UBN RTYOYNBFSH TEYOYS, LHDB ENH YDFY. TSBMSh, UFP UPUED OE RPOINBEF RP-LPYBYUSHY.
22 OPSVTS.
WHAT ABOUT HMYGH. pJYZEFSH! lBLPC, PLBSHCHCHBEFUUS PZTPNOSHCHK NYT! hVEDYMYUSH U LPFPN CH FPN, UFP ABOUT UCHEFE EUFSH CHEEY, ZPTBDP VPMSHYYE, YUEN C#RB OBYEK IPSKLY.
23 OPSVTS.
teyymy pufbfshus ABOUT HMYGE U OPYUECHLPK. URBMY ABOUT FARMPFTBUUE. LPF CHUA OPYUSH VEZBM PE UOE Y RYOBM NEOS MBRBNY. oE URBMPUSH. rPFPNKh ЪBZMSDSCCHBM H PLOB. pDOB VBVLB, LBCEFUS, NEOS HCHYDEMB. lTYLOHMB: "oENGSCH CH ZPTPDE!" Y BRHMSHOHMB CH NEOS LBTFPYLPK.
24 OPSVTS.
CHUFTEFYMY DCHPTCHSCHI LPFCH. urtbychbmy, U LBLPZP NShch TBKPOB, Y EUFSH MY UP? ULBBMY, UFP OEF OYUEZP Y RPYMY DBMSHYE. LPF ULBBM, UFP MEZLP PFDEMBMYUSH.
25 OPSVTS.
LPF OBYUBM OSHCHFSH Y LBOAYUIFSH. ZPCHPTYF, UFP OE NPTSEF VEI MPFLB, FBL LBL PO YYOFEMMYZEOFOPC WENSHY. rTYYMPUSH CHPCHTBEBFSHUS. PUFBMYUSH ABOUT OPYUSH DPNB. pF OEYUEZP DEMBFSh UFHYUBM RP VBFBTESN.
26 OPSVTS.
rTEDMPTSYM LPFC RPKFY EEE RPZHMSFSh. FPF UPUMBMUS ABOUT VPMSHOKHA RSFLH. rTYYMPUSH PUFBFSHUS DPNB. PUEOSH ULHYUOP. UFHYUBM RP VBFBTESN OEPDOPLTBFOP.
27 OPSVTS.
uFPR! pFLHDB X LPFB RSFLB? CHPF VTEIMP VMPIBUFPE! LUFBFY, DECUFCHYFEMSHOP VMPIBUFPE! yULBM DHUF, VOLUME ZHFBMYO. obNBBM EZP, RPLB FPF URBM. FERETSCH PO - LPF oEMSHUPOB nBODEMSCH. lPZDB CHUFTEYUBA, WOYNBA YMSRKH Y LMBOSAUSH. LPF ZPCHPTYF, YuFP S - YDYPF.
28 OPSVTS.
rTYIPDYM UPUED. pFNShM LPFB.
29 OPSVTS.
UNPFTEMY FEMECHYPT. LPF PFLBSHCHCHBEFUS UNPFTEFSH "dPNBYOYK". RPUFPSOOP RETELMAYUBEF ABOUT "dPN-2.
30 OPSVTS.
tBUULBJSCHCHBM LPFH P FEPTYY yTEDYOZETB. rTPCHEMY LURETYNEOF. LPF CHEUSH DEOSH RTPUYDEM CH LPTPVLE. chshchme oh tsychpk, oh netfchshchk. FEPTYS DPLBEBOB. yMY OEF.
1 DERBVTS.
JINB. DHNBMY U LPFPN, ZDE VKhDEN PFNEYUBFSH OPCHSHCHK ZPD. TEYMYMY, UFP ABOUT LHIOE.
2 DERBVTS.
LPF PVSCHRBMUS NHLPC. FERETSH PO - bDERF VEMPZP PTDEOB. rTPPDPMTSBA UOYNBFSH YMSRKh Y LMBOSFShUS. rTPPDPMTSBEF OBSCCHBFSH NEOS YDYPFPN. PI HC LFB BTYUFPLTBFIS...
3 DEBLVTS.
rTYIPDYM UPUED. pFNShM LPFB.
4 DEBLVTS.
OPYUSHA TBUULBSCCHBMY DTHZ DTHZH UFTBYOSCHE YUFPTYY. LPF UDBMUS ABOUT NPNEOPHE P yuETOPN CHEFETYOBTE Y RPRTPUYM CHLMAYUYFSH ABOUT OPYUSH UCHEF.
5 DEBLVTS.
rTYIPDYM UPUED. ULBBM ENH, UFP X OBU CHUE OPTNBMSHOP. UPUED RPYEM PFNSCHCHBFSH YFBOSHCH.
6 DEBLVTS.
bChFTB RTIETSBEF IPSKLB. b RPYENH VSC UPDATE TBVTPUBFSH EE YNPFLY RP LCHBTFYTE? RYODAMEK FP OE NOE RPMHYUBFSH!
7 DEBLVTS.
xTB! rTYEEIBMB! with DBCE UPULHUYMUS HCE. about TBDPUFSI HTPOYM ZPTYPL U GCHEFLPN. pFLHDB LPF OBEF NPA NBFS? hhh?
8 DEBLVTS.
uFP? bBNC? bB IBIBMS? oX ffp khtse umyylpn...
9 DERBVTS.
iBIBMSH ULPTP RTYYMEF UCHBFPCH. UBN, OBCHETOPE, VPIFUUS RTYIPDYFSH. OBEF, YUEN FFP NPTSEF BLPOYUIFSHUS...
10 DEBLVTS.
pTZBOYKHEN U LPFPN DCHYTSEOYE UPRTPPFYCHMEOYS. iBML ULBBM, UFP CHUE FMEO Y CHPPVEE, PO HTS RPYUFY RPOBM DEO Y ULPTP DPUFYZOEF OYTCHOSHCH. b CHUE NYTULPE EZP OE YOFETEUKHEF. with DKHNBM, UFP PO - LNP, B PO PLBBMUS VHDDYUFPN.
11 DEBLVTS.
ABOUT CHSCHVPTBI LPNBOYTB YFBVB PRPMYUEOYS RTPY'PYEM TBULPM. rPUME RPDCHEDEOYS YFPZCH FBKOPZP ZPMPUCHBOYS, VSCHMY PYASCHMEOSCH UMEDHAEIE TEEKHMSHFBFSCH. LPF - PDYO ZPMPU, dPNCHPK - PDYO ZPMPU. rPUME PRIMEHIY UIFHBHYS YENEOIMBUSH. LPF - OPMSH ZPMPUCH, dPNCHPK - DCHB ZPMPUB. EDYOPZMBOOOP, FPCHBTEYEY!
12 DEBLVTS.
UIFHBHYS ABOUT ZTBOY LTYFYUEULPK. iBIBMSh RPDBTYM IPSKLE LPMSHGP. LPOEYUOP TSE, OPYUSHA S EZP URET Y URTSFBM CH LMBDPCHLE. iPSKLB RPZMSDSCHCHBEF ABOUT LPFB, LPF PFLTPCHEOOP RBOILHEF Y RHYUYF ABOUT NEOS UCHPY ZMBALY. rTEDMPTSYM ENH UIPDYFSH L PLHMYUVH.
13 DEBLVTS.
UMHYBMY U LPFPN DBV UFER. according to ZPCHPTYF, UFP LFP NPDOP. x iBMLB UMHYUYMUS RTYUFHR RYMERUYY. b NOE RPOTBCHYMPUSH, OYYUEZP... yNRTPCHYYTHA ABOUT VBFBTESI. RP NPENH, RPIPCE.
14 DEBLVTS.
rPYEM WEZ. LPF ZPCHPTYF, UFP EUMY EUFSH UOETSYOLY, FP DPVBCHMSEFUS +50 L HDBYUE Y YOFEMMELPHH. ULBBM ENKH, YuFP EUMY CHSCHMYYSCHCHBFSH UCHPY YBTHODKHMSCH, FP PF YOFEMMELFB PFOINBEFUS NYOKHU 50. upymyush OB FPN, YuFP FP OB FP Y CHSHCHIPDYF.
15 DEBLVTS.
rTYYMY UCHBFSCH. preTBGYS "YUYUFSHCHK RBURPTF - YUYUFBS UPCHEUFSH" OBYUBMBUSH. LPF OBUFBYCHBM ABOUT OBCHBOY "VKhTS CH LCHBTFYTE". pVYASUOYM ENH, UFP IBFLOYUSH. chPTBTSEOIK VPMSHIE OE RPUFHRBMP.
16 DEBLVTS.
CHUETB EME CHSHCHRTCHPDYMY. LET'S LEAVE CHPME IPSKLY Y ЪCHHLBNY YNYFYTPCHBM OECHBTEOYE. UChBFShch LPUYMYUSH, OP RTPDPMTSBMY ZOHFSH UCHPE. LPF TBUGBTBRBM YN OPZY, YB YuFP VSHM ЪBRETF CH LMBDPCHLE. OP ZETPYUEULY RTPPDPMTSYM CHEUFY PFFHDB DYCHETUYPOOKHA VPTSHVKH, CHSHLTYLYCHBS MPHOZY: "lBLPZP IETB RTYRETMYUSH?" REPTOSHCHE". bB RPUMEDOYK PVYASCHYM ENH CHSHCHZPCHPT Y OBRTEFYM UNPFTEFSH "ZMHIBTS".
17 DERBVTS.
iBML ULBBM, UFP UPRTPFYCHMEOYE CHOEYOYN PVUFPFSFEMSHUFCHBN - RHFSH L UBNPTBBTKHYEOYA. ChPF FBL CHUFBM RPUTEDY OPYUY, ULBBM, CHADPIOKHM Y MEZ DBMSHY URBFSH. RETEZMSOKHMYUSH U LPFPN Y DPZCHPTYMYUSH URBFSH RP PYUETEDY.
18 DEBLVTS.
IPSKLB CHCHUA ZPFCHYFUS L UCHBDSHVE. ABOUT SOCHBTSH. ULTP RTYEDEF MAVYNBS OBNY YOYEDYO YIDBO. pVUHTSDBMY RMBO DBMSHOEKYI DECUFCHYK. LPF HUOHM, LBL CHUEZDB, CHOEBROP.
19 DEBLVTS.
pFRTBCHYMY U ZPMKHVSNY RYUSHNP DEDKH nPTPЪKH. with RPRTPUYM OPCHHA FEFTBDLH YOE MEEFSH L OBN YUETE CHEOFIMSGYA, iBML - RPDBTPYUOPE YIDBOYE bVIYDIBTNSCH, B LPF - CEMFPZP TEJYOPZP HFEOLB. oE, OH CHTPDE CHETPUMPE TSYCHPFOPE... 19 DERBVTS. OPYUSHA CHYDEM, LBL iBML ChPJOYUUS OBD ENMEK. PLBBMPUSH, IPSKLB UMHYUBKOP ROHMB EZP PE UOE.
20 DEBLVTS.
rPMKHYUYMY PF ZPMHVEK PFUEF P DPUFBCHLE Y RTYZMBYOEOYE ABOUT UBKF ЪOBLPNUFCH. lBL PFLMAYUIFSH LFH HUMHZH? dPUFBMY HCE.
21 DERBVTS.
IPSKLB RTYCHEMB RMBFSE. CHUE FBLY LTBUICHBS POB X OBU... LPF RHUFYM UMEKH Y HVETSBM CH LMBDPCHLH. uydjf, rtyyyyfbef.
22 DEBLVTS.
dYULHFYTPCHBM U iBMLPN. хЪOBM ЪOBYUEOYE UMCHB "DYULKHFYTPCHBM". UPVBLECHYU HNEO, BLACK!
23 DEBLVTS.
hTSYOBMY RTY STUDY. ChSCHVIMP RTPVLY, TsDBMY LMELFTYLB. iBML ULBBM, YUFP PZPOSH - EUFSH OBYUBMP YUEFSHTEI UFI... chRTPYUEN, OECHBTsOP... RETETSYCHBA, UFP PO NPTCEF PVTBFIFSH LPFB CH UCHPA CHETKH. ON X NEOS FBLPK DPCHETYUYCHSHCHK.
25 DERBVTS.
iTSROHMY U LPFPN CHBMETSHSOLCH b LBFPMYUEULPE TPTSDEUFCHP. OH B YUEN OE RPCHPD?
27 DEBLVTS.
rPNPZBMY IPSKLE OBTTSBFSH EMLH. LPF TBYVYM YZTHYLKH. UYDYN CH YLBZHKH. rPRTPUYM NEOS RTYTSBFSH EZP HYY L ZPMPCHE, YuFPVSHCHOE VSCHMP CHYDOP. UITSH, RTYTSYNBA.
29 DEBLVTS.
xTB! RPUMEBCHFTB OPCHSHCHK ZPD!
30 DERBVTS.
rTYZPFPCHYM RPDBTLY UCHPYN DPNBYOYN. LPFH RPDBTA OEDEMSHOSCHK BVPOENEOF ABOUT "RPYUEUBFSH IB HIPN", iBMLH - BTPNB-UCHEYUH, IPSKLE CHETOKH LPMSHGP, OP RTYDEFUS RPBYNUFCHPCHBFSH BTPNB-UCHEYUH. iBIBMA - NPY UBNSHCHE MKHYUYE RPTSEMBOIS.
31 DERBVTS.
12: 40
zPFCHINUS L RTBDOILKH. rPNPZBEN IPSKLE ZPFCHYFSH. with UMETSH IB PZOEN, LPF RSCHFBEFUS YUYUFYFSH LBTFPYLH, LBFBS HER RP CHUEK LCHBTFYTE, iBML UPETGBEF. OH, LBL ZPCHPTYFUS, YUEN NPTSEN...
15: 30
RTYYEM IBIBMSh. rPLB PO UOYNBM LHTFLKH, S ChЪVPMFBM VKhFShMlKh Ybnrboulpzp. rPCHBM CHUEI. WIDYN, ZDEN. rPRTPUYM LPFB OE TTSBFSH TBOSHIE READING, YVP RBMECHP. - nHTSYL RPIOBLPNYMUS CH VBTE U OENPMPDPK, OP RTYCHMELBFEMSHOPC 58-MEFOEK DBNPK. CHSHCHRYMY OENOPZP, RPVPMFBMY, FHF POB ZPCHPTYF:
— fshch OILPZDB OE RTPVPCHBM CHFTPEN, U NBFETSHA Y DPULPK PDOPCHTENEOOP?
- oEF.
- b IPFEM VSC?
— urtbychbeysh! lPOEYUOP IPFEM VSC!
- OH FPZDB FEVE RPCHEMP, RPEIBMY LP NOE.
rTYYECTSBAF L OEK DPNPK, DBNB PFLTSCHCHBEF DCHETSH Y LTYUYF CHOHFTSH:
"nBNB, FS EEE OE URYYSH?!.."
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